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std::adjacent_find
Defined in header <algorithm> |
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(1) | ||
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(until C++20) | |
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(since C++20) | |
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(2) | (since C++17) |
(3) | ||
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(until C++20) | |
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(since C++20) | |
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(4) | (since C++17) |
Searches the range [
first
,
last
)
for two consecutive equal elements.
operator==
.
p
.
policy
. These overloads do not participate in overload resolution unless
|
(until C++20) |
|
(since C++20) |
Parameters
first, last | - | the range of elements to examine |
policy | - | the execution policy to use. See execution policy for details. |
p | - | binary predicate which returns true if the elements should be treated as equal. The signature of the predicate function should be equivalent to the following:
While the signature does not need to have |
Type requirements | ||
-ForwardIt must meet the requirements of LegacyForwardIterator. |
Return value
An iterator to the first of the first pair of identical elements, that is, the first iterator it
such that *it == *(it + 1)
for (1,2) or p(*it, *(it + 1)) != false
for (3,4).
If no such elements are found, last
is returned.
Complexity
std::min((result - first) + 1, (last - first) - 1)
applications of the predicate where result
is the return value.
O(last - first)
applications of the corresponding predicate.
Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies,std::terminate
is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory,
std::bad_alloc
is thrown.
Possible implementation
adjacent_find (1) |
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adjacent_find (3) |
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Example
#include <algorithm>
#include <functional>
#include <iostream>
#include <vector>
int main()
{
std::vector<int> v1 {0, 1, 2, 3, 40, 40, 41, 41, 5};
auto i1 = std::adjacent_find(v1.begin(), v1.end());
if (i1 == v1.end())
std::cout << "No matching adjacent elements\n";
else
std::cout << "The first adjacent pair of equal elements is at "
<< std::distance(v1.begin(), i1) << ", *i1 = "
<< *i1 << '\n';
auto i2 = std::adjacent_find(v1.begin(), v1.end(), std::greater<int>());
if (i2 == v1.end())
std::cout << "The entire vector is sorted in ascending order\n";
else
std::cout << "The last element in the non-decreasing subsequence is at "
<< std::distance(v1.begin(), i2) << ", *i2 = " << *i2 << '\n';
}
Output:
The first adjacent pair of equal elements is at 4, *i1 = 40
The last element in the non-decreasing subsequence is at 7, *i2 = 41
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 240 | C++98 | the predicate was applied std::find (first, last, value) - first timesfor (1,3), where value was never defined |
applied std::min( (result - first) + 1, (last - first) - 1) times |
See also
removes consecutive duplicate elements in a range (function template) |
|
(C++20)
|
finds the first two adjacent items that are equal (or satisfy a given predicate) (niebloid) |
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