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std::partition_point
Defined in header <algorithm> |
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---|---|---|
|
(since C++11) (until C++20) |
|
|
(since C++20) |
Examines the partitioned (as if by std::partition
) range [
first
,
last
)
and locates the end of the first partition, that is, the first element that does not satisfy p
or last
if all elements satisfy p
.
Parameters
first, last | - | the partitioned range of elements to examine |
p | - | unary predicate which returns true for the elements found in the beginning of the range. The expression |
Type requirements | ||
-ForwardIt must meet the requirements of LegacyForwardIterator. |
||
-UnaryPredicate must meet the requirements of Predicate. |
Return value
The iterator past the end of the first partition within [
first
,
last
)
or last
if all elements satisfy p
.
Complexity
Given N = std::distance(first, last)
, performs O(log N) applications of the predicate p
.
However, for non-LegacyRandomAccessIterators, the number of iterator increments is O(N).
Notes
This algorithm is a more general form of std::lower_bound
, which can be expressed in terms of std::partition_point
with the predicate [&](auto const& e) { return e < value; });
.
Possible implementation
|
Example
#include <algorithm>
#include <array>
#include <iostream>
#include <iterator>
auto print_seq = [](auto rem, auto first, auto last)
{
for (std::cout << rem; first != last; std::cout << *first++ << ' ') {}
std::cout << '\n';
};
int main()
{
std::array v {1, 2, 3, 4, 5, 6, 7, 8, 9};
auto is_even = [](int i) { return i % 2 == 0; };
std::partition(v.begin(), v.end(), is_even);
print_seq("After partitioning, v: ", v.cbegin(), v.cend());
const auto pp = std::partition_point(v.cbegin(), v.cend(), is_even);
const auto i = std::distance(v.cbegin(), pp);
std::cout << "Partition point is at " << i << "; v[" << i << "] = " << *pp << '\n';
print_seq("First partition (all even elements): ", v.cbegin(), pp);
print_seq("Second partition (all odd elements): ", pp, v.cend());
}
Possible output:
After partitioning, v: 8 2 6 4 5 3 7 1 9
Partition point is at 4; v[4] = 5
First partition (all even elements): 8 2 6 4
Second partition (all odd elements): 5 3 7 1 9
See also
(C++11)
|
finds the first element satisfying specific criteria (function template) |
(C++11)
|
checks whether a range is sorted into ascending order (function template) |
returns an iterator to the first element not less than the given value (function template) |
|
(C++20)
|
locates the partition point of a partitioned range (niebloid) |
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