std::ranges::move_backward, std::ranges::move_backward_result

template< std::bidirectional_iterator I1, std::sentinel_for<I1> S1,
          std::bidirectional_iterator I2 >
requires  std::indirectly_movable<I1, I2>
constexpr move_backward_result<I1, I2>
          move_backward( I1 first, S1 last, I2 result );

template< ranges::bidirectional_range R, std::bidirectional_iterator I >
requires  std::indirectly_movable<ranges::iterator_t<R>, I>
constexpr move_backward_result<ranges::borrowed_iterator_t<R>, I>
          move_backward( R&& r, I result );

template< class I, class O >
  using move_backward_result = ranges::in_out_result<I, O>;

The elements in the moved-from range will still contain valid values of the appropriate type, but not necessarily the same values as before the move, as if using *(result - n) = ranges::iter_move(last - n) for each integer n, where 0 ≤ n < N.

The function-like entities described on this page are niebloids, that is:

• Explicit template argument lists may not be specified when calling any of them.
• None of them is visible to argument-dependent lookup.
• When one of them is found by normal unqualified lookup for the name to the left of the function-call operator, it inhibits argument-dependent lookup.

In practice, they may be implemented as function objects, or with special compiler extensions.

Parameters

Return value

{last, result - N}.

Complexity

Notes

When moving overlapping ranges, ranges::move is appropriate when moving to the left (beginning of the destination range is outside the source range) while ranges::move_backward is appropriate when moving to the right (end of the destination range is outside the source range).

Possible implementation

struct move_backward_fn {
  template<std::bidirectional_iterator I1, std::sentinel_for<I1> S1,
           std::bidirectional_iterator I2>
    requires std::indirectly_movable<I1, I2>
      constexpr ranges::move_backward_result<I1, I2>
        operator()( I1 first, S1 last, I2 result ) const {
          auto i {last};
          for (; i != first; *--result = ranges::iter_move(--i));
          return {std::move(last), std::move(result)};
        }
 
  template<ranges::bidirectional_range R, std::bidirectional_iterator I>
    requires std::indirectly_movable<ranges::iterator_t<R>, I>
      constexpr ranges::move_backward_result<ranges::borrowed_iterator_t<R>, I>
        operator()( R&& r, I result ) const {
          return (*this)(ranges::begin(r), ranges::end(r), std::move(result));
        }
};
 
inline constexpr move_backward_fn move_backward{};

Example

#include <algorithm>
#include <iostream>
#include <string>
#include <string_view>
#include <vector>
 
using Vec = std::vector<std::string>;
 
void print(std::string_view rem, Vec const& vec) {
    std::cout << rem << "[" << vec.size() << "]: ";
    for (const std::string& s : vec)
        std::cout << (s.size() ? s : std::string{"·"}) << ' ';
    std::cout << '\n';
}
 
int main()
{
    Vec a{"▁", "▂", "▃", "▄", "▅", "▆", "▇", "█"};
    Vec b(a.size());
 
    print("Before move:\n" "a", a);
    print("b", b);
 
    std::ranges::move_backward(a, b.end());
 
    print("\n" "Move a >> b:\n" "a", a);
    print("b", b);
 
    std::ranges::move_backward(b.begin(), b.end(), a.end());
    print("\n" "Move b >> a:\n" "a", a);
    print("b", b);
 
    std::ranges::move_backward(a.begin(), a.begin()+3, a.end());
    print("\n" "Overlapping move a[0, 3) >> a[5, 8):\n" "a", a);
}

Before move:
a[8]: ▁ ▂ ▃ ▄ ▅ ▆ ▇ █
b[8]: · · · · · · · ·
 
Move a >> b:
a[8]: · · · · · · · ·
b[8]: ▁ ▂ ▃ ▄ ▅ ▆ ▇ █
 
Move b >> a:
a[8]: ▁ ▂ ▃ ▄ ▅ ▆ ▇ █
b[8]: · · · · · · · ·
 
Overlapping move a[0, 3) >> a[5, 8):
a[8]: · · · ▄ ▅ ▁ ▂ ▃

See also