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std::rotate_copy
Defined in header <algorithm> |
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| (1) | ||
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(until C++20) | |
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(since C++20) | |
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(2) | (since C++17) |
1) Copies the elements from the range
[first, last), to another range beginning at d_first in such a way, that the element *(n_first) becomes the first element of the new range and *(n_first - 1) becomes the last element.
The behavior is undefined if either
[first, n_first) or [n_first, last) is not a valid range, or the source and destination ranges overlap.
2) Same as (1), but executed according to
policy. This overload does not participate in overload resolution unless
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(until C++20) |
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(since C++20) |
Parameters
| first, last | - | the range of elements to copy |
| n_first | - | an iterator to an element in [first, last) that should appear at the beginning of the new range |
| d_first | - | beginning of the destination range |
| policy | - | the execution policy to use. See execution policy for details. |
| Type requirements | ||
-ForwardIt, ForwardIt1, ForwardIt2 must meet the requirements of LegacyForwardIterator. |
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-OutputIt must meet the requirements of LegacyOutputIterator. |
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Return value
Output iterator to the element past the last element copied.
Complexity
linear in the distance between first and last.
Exceptions
The overload with a template parameter named ExecutionPolicy reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicyis one of the standard policies,std::terminateis called. For any otherExecutionPolicy, the behavior is implementation-defined. - If the algorithm fails to allocate memory,
std::bad_allocis thrown.
Possible implementation
See also the implementations in libstdc++, libc++, and MSVC STL.
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Example
#include <algorithm>
#include <iostream>
#include <iterator>
#include <vector>
int main()
{
std::vector<int> src {1, 2, 3, 4, 5};
std::vector<int> dest(src.size());
auto pivot = std::find(src.begin(), src.end(), 3);
std::rotate_copy(src.begin(), pivot, src.end(), dest.begin());
for (int i : dest)
std::cout << i << ' ';
std::cout << '\n';
// copy the rotation result directly to the std::cout
pivot = std::find(dest.begin(), dest.end(), 1);
std::rotate_copy(dest.begin(), pivot, dest.end(),
std::ostream_iterator<int>(std::cout, " "));
std::cout << '\n';
}
Output:
3 4 5 1 2
1 2 3 4 5
See also
| rotates the order of elements in a range (function template) |
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(C++20)
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copies and rotate a range of elements (niebloid) |
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