std::chrono::year_month_day::year_month_day
year_month_day() = default; |
(1) | (since C++20) |
constexpr year_month_day( const std::chrono::year& y, const std::chrono::month& m, const std::chrono::day& d ) noexcept; |
(2) | (since C++20) |
constexpr year_month_day( const std::chrono::year_month_day_last& ymdl ) noexcept; |
(3) | (since C++20) |
constexpr year_month_day( const std::chrono::sys_days& dp ) noexcept; |
(4) | (since C++20) |
explicit constexpr year_month_day( const std::chrono::local_days& dp ) noexcept; |
(5) | (since C++20) |
Constructs a year_month_day
object.
1) Default constructor leaves the date uninitialized.
2) Constructs a
year_month_day
object that stores the year
y
, month
m
and day
d
.
3) Constructs a
year_month_day
object that stores the year
ymdl.year()
, month
ymdl.month()
and day
ymdl.day()
.
4) Constructs a
year_month_day
object that represent the same date as the one represented by
dp
.
5) Constructs a
year_month_day
object that represent the same date as the one represented by
dp
, as if by
year_month_day(sys_days(dp.time_since_epoch()))
.
Constructors (3-4) define implicit conversions from std::chrono::year_month_day_last
and std::chrono::sys_days
, respectively.
For any year_month_day
object ymd
representing a valid date (ymd.ok() == true
), converting ymd
to sys_days
and back yields the same value.
Notes
A year_month_day
can also be created by combining one of the partial-date types std::chrono::year_month
and std::chrono::month_day
with the missing component (day and year, respectively) using operator/
.
See also
(C++20)
|
conventional syntax for Gregorian calendar date creation (function) |
© cppreference.com
Licensed under the Creative Commons Attribution-ShareAlike Unported License v3.0.
https://en.cppreference.com/w/cpp/chrono/year_month_day/year_month_day