std::inout_ptr
Defined in header <memory> |
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template< class Pointer = void, class Smart, class... Args > auto inout_ptr( Smart& s, Args&&... args ); |
(since C++23) |
Returns an inout_ptr_t with deduced template arguments that captures arguments for resetting by reference.
The program is ill-formed if construction of the return value (see below) is ill-formed.
Parameters
| s | - | the object (typically a smart pointer) to adapt |
| args... | - | the arguments for resetting to capture |
Return value
std::inout_ptr_t<Smart, P, Args&&>(s, std::forward<Args>(args)...), where P is.
-
Pointer, ifPointeris not same asvoid, - otherwise,
Smart::pointer, if it is valid and denotes a type, - otherwise,
Smart::element_type*, ifSmart::element_typeis valid and denotes a type, - otherwise,
std::pointer_traits<Smart>::element_type*.
Notes
Users may specify the template argument for the template parameter Pointer, in order to interoperate with foreign functions that take a Pointer*.
As all arguments for resetting are captured by reference, the returned inout_ptr_t should be a temporary object destroyed at the end of the full-expression containing the call to the foreign function, in order to avoid dangling references.
Feature testing macro: __cpp_lib_out_ptr.
Example
See also
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(C++23)
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creates an out_ptr_t with an associated smart pointer and resetting arguments (function template) |
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(C++14)(C++20)
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creates a unique pointer that manages a new object (function template) |
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(C++20)
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creates a shared pointer that manages a new object (function template) |
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