std::conj(std::complex)

template< class T > 
std::complex<T> conj( const std::complex<T>& z );

template< class T > 
constexpr std::complex<T> conj( const std::complex<T>& z );

std::complex<float>       conj( float f );
std::complex<double>      conj( double f );
std::complex<long double> conj( long double f );

constexpr std::complex<float>       conj( float f );
constexpr std::complex<double>      conj( double f );
constexpr std::complex<long double> conj( long double f );

template< class FloatingPoint >
constexpr std::complex<FloatingPoint> conj( FloatingPoint f );

template< class Integer >
constexpr std::complex<double> conj( Integer i );

template< class Integer >
constexpr std::complex<double> conj( Integer i );

Parameters

Return value

Notes

The additional overloads are not required to be provided exactly as (A,B). They only need to be sufficient to ensure that for their argument num:

• If num has a standard(until C++23) floating-point type T, then std::conj(num) has the same effect as std::conj(std::complex<T>(num)).
• Otherwise, if num has an integer type, then std::conj(num) has the same effect as std::conj(std::complex<double>(num)).

Example

#include <complex>
#include <iostream>
 
int main()
{
    std::complex<double> z(1.0, 2.0);
    std::cout << "The conjugate of " << z << " is " << std::conj(z) << '\n'
              << "Their product is " << z * std::conj(z) << '\n';
}

The conjugate of (1,2) is (1,-2)
Their product is (5,0)

See also