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std::cbrt, std::cbrtf, std::cbrtl
Defined in header <cmath> |
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(1) | ||
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(until C++23) | |
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(since C++23) (constexpr since C++26) |
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(2) | (since C++11) (constexpr since C++26) |
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(3) | (since C++11) (constexpr since C++26) |
Additional overloads (since C++11) | ||
Defined in header <cmath> |
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(A) | (constexpr since C++26) |
num
. The library provides overloads of std::cbrt
for all cv-unqualified floating-point types as the type of the parameter.(since C++23)
A) Additional overloads are provided for all integer types, which are treated as double. | (since C++11) |
Parameters
num | - | floating-point or integer value |
Return value
If no errors occur, the cube root of num
(\(\small{\sqrt[3]{num} }\)3√num), is returned.
If a range error occurs due to underflow, the correct result (after rounding) is returned.
Error handling
Errors are reported as specified in math_errhandling
.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
- if the argument is ±0 or ±∞, it is returned, unchanged.
- if the argument is NaN, NaN is returned.
Notes
std::cbrt(num)
is not equivalent to std::pow(num, 1.0 / 3)
because the rational number \(\small{\frac1{3} }\)1/3 is typically not equal to 1.0 / 3
and std::pow
cannot raise a negative base to a fractional exponent. Moreover, std::cbrt(num)
usually gives more accurate results than std::pow(num, 1.0 / 3)
(see example).
The additional overloads are not required to be provided exactly as (A). They only need to be sufficient to ensure that for their argument num
of integer type, std::cbrt(num)
has the same effect as std::cbrt(static_cast<double>(num))
.
Example
#include <cmath>
#include <iomanip>
#include <iostream>
#include <limits>
int main()
{
std::cout
<< "Normal use:\n"
<< "cbrt(729) = " << std::cbrt(729) << '\n'
<< "cbrt(-0.125) = " << std::cbrt(-0.125) << '\n'
<< "Special values:\n"
<< "cbrt(-0) = " << std::cbrt(-0.0) << '\n'
<< "cbrt(+inf) = " << std::cbrt(INFINITY) << '\n'
<< "Accuracy and comparison with `pow`:\n"
<< std::setprecision(std::numeric_limits<double>::max_digits10)
<< "cbrt(343) = " << std::cbrt(343) << '\n'
<< "pow(343,1.0/3) = " << std::pow(343, 1.0 / 3) << '\n'
<< "cbrt(-343) = " << std::cbrt(-343) << '\n'
<< "pow(-343,1.0/3) = " << std::pow(-343, 1.0 / 3) << '\n';
}
Possible output:
Normal use:
cbrt(729) = 9
cbrt(-0.125) = -0.5
Special values:
cbrt(-0) = -0
cbrt(+inf) = inf
Accuracy and comparison with `pow`:
cbrt(343) = 7
pow(343,1.0/3) = 6.9999999999999991
cbrt(-343) = -7
pow(-343,1.0/3) = -nan
See also
(C++11)(C++11)
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raises a number to the given power (\(\small{x^y}\)xy) (function) |
(C++11)(C++11)
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computes square root (\(\small{\sqrt{x}}\)√x) (function) |
(C++11)(C++11)(C++11)
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computes square root of the sum of the squares of two or three(since C++17) given numbers (\(\scriptsize{\sqrt{x^2+y^2}}\)√x2+y2), (\(\scriptsize{\sqrt{x^2+y^2+z^2}}\)√x2+y2+z2)(since C++17) (function) |
C documentation for cbrt |
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