std::compare_strong_order_fallback

inline namespace /* unspecified */ {
    inline constexpr /* unspecified */
        compare_strong_order_fallback = /* unspecified */;
}

template< class T, class U >
    requires /* see below */
constexpr std::strong_ordering
    compare_strong_order_fallback(T&& t, U&& u) noexcept(/* see below */);

Performs three-way comparison on t and u and produces a result of type std::strong_ordering, even if the operator <=> is unavailable.

Let t and u be expressions and T and U denote decltype((t)) and decltype((u)) respectively, std::compare_strong_order_fallback(t, u) is expression-equivalent to:

• If std::is_same_v<std::decay_t<T>, std::decay_t<U>> is true:
  • std::strong_order(t, u), if it is a well-formed expression;
  • otherwise,

t == u ? std::strong_ordering::equal :
t < u  ? std::strong_ordering::less :
         std::strong_ordering::greater

• In all other cases, std::compare_strong_order_fallback(t, u) is ill-formed, which can result in substitution failure when it appears in the immediate context of a template instantiation.

Expression-equivalent

Expression e is expression-equivalent to expression f, if.

• e and f have the same effects, and
• either both are constant subexpressions or else neither is a constant subexpression, and
• either both are potentially-throwing or else neither is potentially-throwing (i.e. noexcept(e) == noexcept(f)).

Customization point objects

The name std::compare_strong_order_fallback denotes a customization point object, which is a const function object of a literal semiregular class type. For exposition purposes, the cv-unqualified version of its type is denoted as __compare_strong_order_fallback_fn.

All instances of __compare_strong_order_fallback_fn are equal. The effects of invoking different instances of type __compare_strong_order_fallback_fn on the same arguments are equivalent, regardless of whether the expression denoting the instance is an lvalue or rvalue, and is const-qualified or not (however, a volatile-qualified instance is not required to be invocable). Thus, std::compare_strong_order_fallback can be copied freely and its copies can be used interchangeably.

Given a set of types Args..., if std::declval<Args>()... meet the requirements for arguments to std::compare_strong_order_fallback above, __compare_strong_order_fallback_fn models
.

• std::invocable<__compare_strong_order_fallback_fn, Args...>,
• std::invocable<const __compare_strong_order_fallback_fn, Args...>,
• std::invocable<__compare_strong_order_fallback_fn&, Args...>, and
• std::invocable<const __compare_strong_order_fallback_fn&, Args...>.
  

Otherwise, no function call operator of __compare_strong_order_fallback_fn participates in overload resolution.

Example

See also