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std::function_ref::operator=

constexpr function_ref& operator=( const function_ref& ) noexcept = default;
(1) (since C++26)
template< class T > 
constexpr function_ref& operator=( T ) = delete;
(2) (since C++26)
1) Copy assignment operator is explicitly-defaulted. std::function_ref satisfies copyable and TriviallyCopyable. This defaulted assignment operator performs a shallow copy of the stored thunk-ptr and bound-entity.
2) User-defined assignment operator is explicitly-deleted if T is not the same type as std::function_ref, std::is_pointer_v<T> is false, and T is not a specialization of std::nontype_t. This overload participates in overload resolution only if the constraints are satisfied in the conditions above.

Return value

*this

See also

(C++26)
constructs a new function_ref object
(public member function)
assigns a new target
(public member function of std::function<R(Args...)>)

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