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std::monostate
Defined in header <variant> |
||
---|---|---|
|
(since C++17) |
Unit type intended for use as a well-behaved empty alternative in std::variant
. In particular, a variant of non-default-constructible types may list std::monostate
as its first alternative: this makes the variant itself default-constructible.
Member functions
(constructor)
(implicitly declared)
|
trivial implicit default/copy/move constructor (public member function) |
(destructor)
(implicitly declared)
|
trivial implicit destructor (public member function) |
operator=
(implicitly declared)
|
trivial implicit copy/move assignment (public member function) |
Non-member functions
std::operator==, !=, <, <=, >, >=, <=>(std::monostate)
|
(1) | (since C++17) |
(2) | ||
|
(since C++17) (until C++20) |
|
|
(since C++20) |
All instances of std::monostate
compare equal.
The |
(since C++20) |
Helper classes
std::hash<std::monostate>
|
(since C++17) |
Specializes the std::hash
algorithm for std::monostate
.
Example
#include <cassert>
#include <iostream>
#include <variant>
struct S
{
S(int i) : i(i) {}
int i;
};
int main()
{
// Without the monostate type this declaration will fail.
// This is because S is not default-constructible.
std::variant<std::monostate, S> var;
assert(var.index() == 0);
try
{
std::get<S>(var); // throws! We need to assign a value
}
catch(const std::bad_variant_access& e)
{
std::cout << e.what() << '\n';
}
var = 42;
std::cout << "std::get: " << std::get<S>(var).i << '\n'
<< "std::hash: " << std::hex << std::showbase
<< std::hash<std::monostate>{}(std::monostate{}) << '\n';
}
Possible output:
std::get: wrong index for variant
std::get: 42
std::hash: 0xffffffffffffe19f
See also
constructs the variant object (public member function) |
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