The test()
method of RegExp
instances executes a search with this regular expression for a match between a regular expression and a specified string. Returns true
if there is a match; false
otherwise.
JavaScript RegExp
objects are stateful when they have the global
or sticky
flags set (e.g., /foo/g
or /foo/y
). They store a lastIndex
from the previous match. Using this internally, test()
can be used to iterate over multiple matches in a string of text (with capture groups).
Parameters
-
str
-
The string against which to match the regular expression. All values are coerced to strings, so omitting it or passing undefined
causes test()
to search for the string "undefined"
, which is rarely what you want.
Return value
true
if there is a match between the regular expression and the string str
. Otherwise, false
.
Description
Use test()
whenever you want to know whether a pattern is found in a string. test()
returns a boolean, unlike the String.prototype.search()
method (which returns the index of a match, or -1
if not found).
To get more information (but with slower execution), use the exec()
method. (This is similar to the String.prototype.match()
method.)
As with exec()
(or in combination with it), test()
called multiple times on the same global regular expression instance will advance past the previous match.
Using test()
Simple example that tests if "hello"
is contained at the very beginning of a string, returning a boolean result.
const str = "hello world!";
const result = /^hello/.test(str);
console.log(result);
The following example logs a message which depends on the success of the test:
function testInput(re, str) {
const midstring = re.test(str) ? "contains" : "does not contain";
console.log(`${str}${midstring}${re.source}`);
}
Using test() on a regex with the "global" flag
When a regex has the global flag set, test()
will advance the lastIndex
of the regex. (RegExp.prototype.exec()
also advances the lastIndex
property.)
Further calls to test(str)
will resume searching str
starting from lastIndex
. The lastIndex
property will continue to increase each time test()
returns true
.
Note: As long as test()
returns true
, lastIndex
will not reset—even when testing a different string!
When test()
returns false
, the calling regex's lastIndex
property will reset to 0
.
The following example demonstrates this behavior:
const regex = /foo/g;
regex.test("foo");
regex.test("foo");
regex.test("barfoo");
regex.test("foobar");
regex.test("foobarfoo");
regex.test("foobarfoo");
regex.test("foobarfoo");
Specifications
Browser compatibility
|
Desktop |
Mobile |
Server |
|
Chrome |
Edge |
Firefox |
Opera |
Safari |
Chrome Android |
Firefox for Android |
Opera Android |
Safari on IOS |
Samsung Internet |
WebView Android |
Deno |
Node.js |
test |
1 |
12 |
1 |
5 |
1 |
18 |
4 |
10.1 |
1 |
1.0 |
4.4 |
1.0 |
0.10.0 |