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numpy.linalg.pinv
linalg.pinv(a, rcond=1e-15, hermitian=False)[source]- 
    
Compute the (Moore-Penrose) pseudo-inverse of a matrix.
Calculate the generalized inverse of a matrix using its singular-value decomposition (SVD) and including all large singular values.
Changed in version 1.14: Can now operate on stacks of matrices
- Parameters
 - 
      
a(…, M, N) array_like- 
        
Matrix or stack of matrices to be pseudo-inverted.
 rcond(…) array_like of float- 
        
Cutoff for small singular values. Singular values less than or equal to
rcond * largest_singular_valueare set to zero. Broadcasts against the stack of matrices. hermitianbool, optional- 
        
If True,
ais assumed to be Hermitian (symmetric if real-valued), enabling a more efficient method for finding singular values. Defaults to False.New in version 1.17.0.
 
 - Returns
 - 
      
B(…, N, M) ndarray- 
        
The pseudo-inverse of
a. Ifais amatrixinstance, then so isB. 
 - Raises
 - 
      
- LinAlgError
 - 
        
If the SVD computation does not converge.
 
 
See also
scipy.linalg.pinv- 
       
Similar function in SciPy.
 scipy.linalg.pinv2- 
       
Similar function in SciPy (SVD-based).
 scipy.linalg.pinvh- 
       
Compute the (Moore-Penrose) pseudo-inverse of a Hermitian matrix.
 
Notes
The pseudo-inverse of a matrix A, denoted
, is defined as: “the matrix that ‘solves’ [the least-squares problem]
,” i.e., if
is said solution, then
is that matrix such that
.
It can be shown that if
is the singular value decomposition of A, then
, where
are orthogonal matrices,
is a diagonal matrix consisting of A’s so-called singular values, (followed, typically, by zeros), and then
is simply the diagonal matrix consisting of the reciprocals of A’s singular values (again, followed by zeros). [1]
References
1- 
      
G. Strang, Linear Algebra and Its Applications, 2nd Ed., Orlando, FL, Academic Press, Inc., 1980, pp. 139-142.
 
Examples
The following example checks that
a * a+ * a == aanda+ * a * a+ == a+:>>> a = np.random.randn(9, 6) >>> B = np.linalg.pinv(a) >>> np.allclose(a, np.dot(a, np.dot(B, a))) True >>> np.allclose(B, np.dot(B, np.dot(a, B))) True 
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 https://numpy.org/doc/1.20/reference/generated/numpy.linalg.pinv.html