tf.math.is_strictly_increasing
Returns True if x is strictly increasing.
tf.math.is_strictly_increasing(
x, name=None
)
Elements of x are compared in row-major order. The tensor [x[0],...] is strictly increasing if for every adjacent pair we have x[i] < x[i+1]. If x has less than two elements, it is trivially strictly increasing.
See also: is_non_decreasing
| Args | |
|---|---|
x |
Numeric Tensor. |
name |
A name for this operation (optional). Defaults to "is_strictly_increasing" |
| Returns | |
|---|---|
Boolean Tensor, equal to True iff x is strictly increasing. |
| Raises | |
|---|---|
TypeError |
if x is not a numeric tensor. |
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Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/versions/r1.15/api_docs/python/tf/math/is_strictly_increasing