The delete()
method of Set
instances removes a specified value from this set, if it is in the set.
On this page
Set.prototype.delete()
Try it
Syntax
js
setInstance.delete(value)
Parameters
-
value
-
The value to remove from
Set
.
Return value
Returns true
if value
was already in Set
; otherwise false
.
Examples
Using the delete() method
js
const mySet = new Set();
mySet.add("foo");
console.log(mySet.delete("bar")); // false; no "bar" element found to be deleted.
console.log(mySet.delete("foo")); // true; successfully removed.
console.log(mySet.has("foo")); // false; the "foo" element is no longer present.
Deleting an object from a set
Because objects are compared by reference, you have to delete them by checking individual properties if you don't have a reference to the original object.
js
const setObj = new Set(); // Create a new set.
setObj.add({ x: 10, y: 20 }); // Add object in the set.
setObj.add({ x: 20, y: 30 }); // Add object in the set.
// Delete any point with `x > 10`.
setObj.forEach((point) => {
if (point.x > 10) {
setObj.delete(point);
}
});
Specifications
Browser compatibility
Desktop | Mobile | Server | ||||||||||||
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
Chrome | Edge | Firefox | Opera | Safari | Chrome Android | Firefox for Android | Opera Android | Safari on IOS | Samsung Internet | WebView Android | Deno | Node.js | ||
delete |
38 | 12 | 13 | 25 | 8 | 38 | 14 | 25 | 8 | 3.0 | 38 | 1.0 | 0.12.0 |
See also
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https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Set/delete