The delete()
method removes a specified value from a Set
object, if it is in the set.
Set.prototype.delete()
Try it
Syntax
delete(value)
Parameters
-
value
-
The value to remove from
Set
.
Return value
Returns true
if value
was already in Set
; otherwise false
.
Examples
Using the delete() method
const mySet = new Set(); mySet.add('foo'); mySet.delete('bar'); // Returns false. No "bar" element found to be deleted. mySet.delete('foo'); // Returns true. Successfully removed. mySet.has('foo'); // Returns false. The "foo" element is no longer present.
Let's check out below how to delete an Object from a Set.
const setObj = new Set(); // Create a new set. setObj.add({x: 10, y: 20}); // Add object in the set. setObj.add({x: 20, y: 30}); // Add object in the set. // Delete any point with `x > 10`. setObj.forEach(function(point){ if (point.x > 10){ setObj.delete(point) } })
Specifications
Browser compatibility
Desktop | Mobile | Server | ||||||||||||
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Chrome | Edge | Firefox | Internet Explorer | Opera | Safari | WebView Android | Chrome Android | Firefox for Android | Opera Android | Safari on IOS | Samsung Internet | Deno | Node.js | |
delete |
38
|
12
|
13
|
11
|
25
|
8
|
38
|
38
|
14
|
25
|
8
|
3.0
|
1.0
|
0.12.0
0.10.0
|
See also
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Licensed under the Creative Commons Attribution-ShareAlike License v2.5 or later.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Set/delete