switch

switch (expression) {
  case value1:
    //Statements executed when the
    //result of expression matches value1
    [break;]
  case value2:
    //Statements executed when the
    //result of expression matches value2
    [break;]
  ...
  case valueN:
    //Statements executed when the
    //result of expression matches valueN
    [break;]
  [default:
    //Statements executed when none of
    //the values match the value of the expression
    [break;]]
}

expression

An expression whose result is matched against each case clause.

case valueN Optional

A case clause used to match against expression. If the expression matches the specified valueN, the statements inside the matching case clause are executed, and then the statements inside all case clauses which follow the matching case clause are executed — until either the end of the switch statement or a break.

default Optional

A default clause; if provided, this clause is executed if the value of expression doesn't match any of the case clauses.

A switch statement first evaluates its expression. It then looks for the first case clause whose expression evaluates to the same value as the result of the input expression (using the strict comparison, ===) and transfers control to that clause, executing the associated statements. (If multiple cases match the provided value, the first case that matches is selected, even if the cases are not equal to each other.)

If no matching case clause is found, the program looks for the optional default clause, and if found, transfers control to that clause, executing the associated statements. If no default clause is found, the program continues execution at the statement following the end of switch. By convention, the default clause is the last clause, but it does not need to be so.

The optional break statement associated with each case label ensures that the program breaks out of switch once the matched statement is executed and continues execution at the statement following switch. If break is omitted, the program continues execution at the next statement in the switch statement. The break statement is not required if a return statement precedes it.

In the following example, if expr evaluates to Bananas, the program matches the value with case case 'Bananas' and executes the associated statement. When break is encountered, the program breaks out of switch and executes the statement following switch. If break were omitted, the statement for the case 'Cherries' would also be executed.

switch (expr) {
  case 'Oranges':
    console.log('Oranges are $0.59 a pound.');
    break;
  case 'Apples':
    console.log('Apples are $0.32 a pound.');
    break;
  case 'Bananas':
    console.log('Bananas are $0.48 a pound.');
    break;
  case 'Cherries':
    console.log('Cherries are $3.00 a pound.');
    break;
  case 'Mangoes':
  case 'Papayas':
    console.log('Mangoes and papayas are $2.79 a pound.');
    break;
  default:
    console.log('Sorry, we are out of ' + expr + '.');
}

console.log("Is there anything else you'd like?");

If you forget a break then the script will run from the case where the criterion is met and will run the cases after that regardless if a criterion was met.

See example here:

var foo = 0;
switch (foo) {
  case -1:
    console.log('negative 1');
    break;
  case 0: // foo is 0 so criteria met here so this block will run
    console.log(0);
    // NOTE: the forgotten break would have been here
  case 1: // no break statement in 'case 0:' so this case will run as well
    console.log(1);
    break; // it encounters this break so will not continue into 'case 2:'
  case 2:
    console.log(2);
    break;
  default:
    console.log('default');
}

Yes, you can! JavaScript will drop you back to the default if it can't find a match:

var foo = 5;
switch (foo) {
  case 2:
    console.log(2);
    break; // it encounters this break so will not continue into 'default:'
  default:
    console.log('default')
    // fall-through
  case 1:
    console.log('1');
}

It also works when you put default before all other cases.

This technique is also commonly called fall-through.

Multi-case : single operation

This method takes advantage of the fact that if there is no break below a case clause it will continue to execute the next case clause regardless if the case meets the criteria. (See the section What happens if I forgot a break?)

This is an example of a single operation sequential case statement, where four different values perform exactly the same.

var Animal = 'Giraffe';
switch (Animal) {
  case 'Cow':
  case 'Giraffe':
  case 'Dog':
  case 'Pig':
    console.log('This animal is not extinct.');
    break;
  case 'Dinosaur':
  default:
    console.log('This animal is extinct.');
}

Multi-case : chained operations

This is an example of a multiple-operation sequential case clause, where, depending on the provided integer, you can receive different output. This shows you that it will traverse in the order that you put the case clauses, and it does not have to be numerically sequential. In JavaScript, you can even mix in definitions of strings into these case statements as well.

var foo = 1;
var output = 'Output: ';
switch (foo) {
  case 0:
    output += 'So ';
  case 1:
    output += 'What ';
    output += 'Is ';
  case 2:
    output += 'Your ';
  case 3:
    output += 'Name';
  case 4:
    output += '?';
    console.log(output);
    break;
  case 5:
    output += '!';
    console.log(output);
    break;
  default:
    console.log('Please pick a number from 0 to 5!');
}

The output from this example:

With ECMAScript 2015 (ES6) support made available in most modern browsers, there will be cases where you would want to use let and const statements to declare block-scoped variables.

Take a look at this example:

const action = 'say_hello';
switch (action) {
  case 'say_hello':
    let message = 'hello';
    console.log(message);
    break;
  case 'say_hi':
    let message = 'hi';
    console.log(message);
    break;
  default:
    console.log('Empty action received.');
}

This example will output the error Uncaught SyntaxError: Identifier 'message' has already been declared which you were not probably expecting.

This is because the first let message = 'hello'; conflicts with second let statement let message = 'hi'; even they're within their own separate case clauses case 'say_hello': and case 'say_hi':. Ultimately, this is due to both let statements being interpreted as duplicate declarations of the same variable name within the same block scope.

We can easily fix this by wrapping our case clauses with brackets:

const action = 'say_hello';
switch (action) {
  case 'say_hello': { // added brackets
    let message = 'hello';
    console.log(message);
    break;
  } // added brackets
  case 'say_hi': { // added brackets
    let message = 'hi';
    console.log(message);
    break;
  } // added brackets
  default: { // added brackets
    console.log('Empty action received.');
  } // added brackets
}

This code will now output hello in the console as it should, without any errors at all.

• if...else