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numpy.cbrt
numpy.cbrt(x, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'cbrt'>
-
Return the cube-root of an array, element-wise.
New in version 1.10.0.
Parameters: x : array_like
The values whose cube-roots are required.
out : ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or
None
, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.where : array_like, optional
Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.
**kwargs
For other keyword-only arguments, see the ufunc docs.
Returns: y : ndarray
An array of the same shape as
x
, containing the cube cube-root of each element inx
. Ifout
was provided,y
is a reference to it.Examples
>>> np.cbrt([1,8,27]) array([ 1., 2., 3.])
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Licensed under the NumPy License.
https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.cbrt.html