numpy.ma.choose

numpy.ma.choose(indices, choices, out=None, mode='raise') [source]

Use an index array to construct a new array from a set of choices.

Given an array of integers and a set of n choice arrays, this method will create a new array that merges each of the choice arrays. Where a value in a is i, the new array will have the value that choices[i] contains in the same place.

Parameters:

a : ndarray of ints This array must contain integers in [0, n-1], where n is the number of choices. choices : sequence of arrays Choice arrays. The index array and all of the choices should be broadcastable to the same shape. out : array, optional If provided, the result will be inserted into this array. It should be of the appropriate shape and dtype. mode : {‘raise’, ‘wrap’, ‘clip’}, optional Specifies how out-of-bounds indices will behave. ‘raise’ : raise an error ‘wrap’ : wrap around ‘clip’ : clip to the range

Returns:

merged_array : array

See also

choose

equivalent function

Examples

>>> choice = np.array([[1,1,1], [2,2,2], [3,3,3]])
>>> a = np.array([2, 1, 0])
>>> np.ma.choose(a, choice)
masked_array(data = [3 2 1],
      mask = False,
      fill_value=999999)