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numpy.arccos
numpy.arccos(x, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'arccos'>-
Trigonometric inverse cosine, element-wise.
The inverse of
cosso that, ify = cos(x), thenx = arccos(y).Parameters: -
x : array_like -
x-coordinate on the unit circle. For real arguments, the domain is [-1, 1]. -
out : ndarray, None, or tuple of ndarray and None, optional -
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or
None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs. -
where : array_like, optional -
This condition is broadcast over the input. At locations where the condition is True, the
outarray will be set to the ufunc result. Elsewhere, theoutarray will retain its original value. Note that if an uninitializedoutarray is created via the defaultout=None, locations within it where the condition is False will remain uninitialized. - **kwargs
-
For other keyword-only arguments, see the ufunc docs.
Returns: -
angle : ndarray -
The angle of the ray intersecting the unit circle at the given
x-coordinate in radians [0, pi]. This is a scalar ifxis a scalar.
Notes
arccosis a multivalued function: for eachxthere are infinitely many numberszsuch thatcos(z) = x. The convention is to return the anglezwhose real part lies in[0, pi].For real-valued input data types,
arccosalways returns real output. For each value that cannot be expressed as a real number or infinity, it yieldsnanand sets theinvalidfloating point error flag.For complex-valued input,
arccosis a complex analytic function that has branch cuts[-inf, -1]and[1, inf]and is continuous from above on the former and from below on the latter.The inverse
cosis also known asacosor cos^-1.References
M. Abramowitz and I.A. Stegun, “Handbook of Mathematical Functions”, 10th printing, 1964, pp. 79. http://www.math.sfu.ca/~cbm/aands/
Examples
We expect the arccos of 1 to be 0, and of -1 to be pi:
>>> np.arccos([1, -1]) array([ 0. , 3.14159265])Plot arccos:
>>> import matplotlib.pyplot as plt >>> x = np.linspace(-1, 1, num=100) >>> plt.plot(x, np.arccos(x)) >>> plt.axis('tight') >>> plt.show() -
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https://docs.scipy.org/doc/numpy-1.17.0/reference/generated/numpy.arccos.html