numpy.char.count

numpy.char.count(a, sub, start=0, end=None)

Returns an array with the number of non-overlapping occurrences of substring sub in the range [start, end].

Calls str.count element-wise.

Parameters

aarray_like of str or unicode

substr or unicode

The substring to search for.

start, endint, optional

Optional arguments start and end are interpreted as slice notation to specify the range in which to count.

Returns

outndarray

Output array of ints.

See also

str.count

Examples

>>> c = np.array(['aAaAaA', '  aA  ', 'abBABba'])
>>> c
array(['aAaAaA', '  aA  ', 'abBABba'], dtype='<U7')
>>> np.char.count(c, 'A')
array([3, 1, 1])
>>> np.char.count(c, 'aA')
array([3, 1, 0])
>>> np.char.count(c, 'A', start=1, end=4)
array([2, 1, 1])
>>> np.char.count(c, 'A', start=1, end=3)
array([1, 0, 0])