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numpy.dot
- numpy.dot(a, b, out=None)
- 
    Dot product of two arrays. Specifically, - If both aandbare 1-D arrays, it is inner product of vectors (without complex conjugation).
- If both aandbare 2-D arrays, it is matrix multiplication, but usingmatmulora @ bis preferred.
- If either aorbis 0-D (scalar), it is equivalent tomultiplyand usingnumpy.multiply(a, b)ora * bis preferred.
- If ais an N-D array andbis a 1-D array, it is a sum product over the last axis ofaandb.
- If - ais an N-D array and- bis an M-D array (where- M>=2), it is a sum product over the last axis of- aand the second-to-last axis of- b:- dot(a, b)[i,j,k,m] = sum(a[i,j,:] * b[k,:,m])
 - Parameters
- 
      - aarray_like
- 
        First argument. 
- barray_like
- 
        Second argument. 
- outndarray, optional
- 
        Output argument. This must have the exact kind that would be returned if it was not used. In particular, it must have the right type, must be C-contiguous, and its dtype must be the dtype that would be returned for dot(a,b). This is a performance feature. Therefore, if these conditions are not met, an exception is raised, instead of attempting to be flexible.
 
- Returns
- 
      - outputndarray
- 
        Returns the dot product of aandb. Ifaandbare both scalars or both 1-D arrays then a scalar is returned; otherwise an array is returned. Ifoutis given, then it is returned.
 
- Raises
- 
      - ValueError
- 
        If the last dimension of ais not the same size as the second-to-last dimension ofb.
 
 See also Examples>>> np.dot(3, 4) 12Neither argument is complex-conjugated: >>> np.dot([2j, 3j], [2j, 3j]) (-13+0j)For 2-D arrays it is the matrix product: >>> a = [[1, 0], [0, 1]] >>> b = [[4, 1], [2, 2]] >>> np.dot(a, b) array([[4, 1], [2, 2]])>>> a = np.arange(3*4*5*6).reshape((3,4,5,6)) >>> b = np.arange(3*4*5*6)[::-1].reshape((5,4,6,3)) >>> np.dot(a, b)[2,3,2,1,2,2] 499128 >>> sum(a[2,3,2,:] * b[1,2,:,2]) 499128
- If both 
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 https://numpy.org/doc/1.19/reference/generated/numpy.dot.html