3.6.4 包含某列的分组最大值的行
任务:对于每件商品,寻找价格最昂贵的经销商.
这个问题可以通过像这样的子查询来解决:
SELECT article, dealer, price
FROM shop s1
WHERE price=(SELECT MAX(s2.price)
FROM shop s2
WHERE s1.article = s2.article)
ORDER BY article;
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
| 0001 | B | 3.99 |
| 0002 | A | 10.99 |
| 0003 | C | 1.69 |
| 0004 | D | 19.95 |
+---------+--------+-------+
前面的示例使用了一个关联的子查询,该子查询可能效率不高(请参见第 13.2.10.7 节“相关子查询”)。解决该问题的其他可能性是在FROM
子句或LEFT JOIN
中使用不相关的子查询。
Uncorrelated subquery:
SELECT s1.article, dealer, s1.price
FROM shop s1
JOIN (
SELECT article, MAX(price) AS price
FROM shop
GROUP BY article) AS s2
ON s1.article = s2.article AND s1.price = s2.price
ORDER BY article;
LEFT JOIN
:
SELECT s1.article, s1.dealer, s1.price
FROM shop s1
LEFT JOIN shop s2 ON s1.article = s2.article AND s1.price < s2.price
WHERE s2.article IS NULL
ORDER BY s1.article;
LEFT JOIN
的工作原理是,当s1.price
处于最大值时,不存在更大的s2.price
值,因此相应的s2.article
值为NULL
。参见第 13.2.9.2 节“ JOIN 子句”。