类 ResourcePropertySource
- java.lang.Object
- org.springframework.core.env.PropertySource<T>
- org.springframework.core.env.EnumerablePropertySource<Map<String,Object>>
- org.springframework.core.env.MapPropertySource
- org.springframework.core.env.PropertiesPropertySource
- org.springframework.core.io.support.ResourcePropertySource
public class ResourcePropertySource extends PropertiesPropertySource
Subclass ofPropertiesPropertySource
that loads aProperties
object from a givenResource
or resource location such as"classpath:/com/myco/foo.properties"
or"file:/path/to/file.xml"
.Both traditional and XML-based properties file formats are supported; however, in order for XML processing to take effect, the underlying
Resource
'sgetFilename()
method must return a non-null
value that ends in".xml"
.- 从以下版本开始:
- 3.1
- 作者:
- Chris Beams, Juergen Hoeller
- 另请参阅:
Resource
,EncodedResource
嵌套类概要
从类继承的嵌套类/接口 org.springframework.core.env.PropertySource
PropertySource.StubPropertySource
字段概要
从类继承的字段 org.springframework.core.env.PropertySource
logger, name, source
构造器概要
构造器 构造器 说明 ResourcePropertySource(String location)
Create a PropertySource based on Properties loaded from the given resource location.ResourcePropertySource(String location, ClassLoader classLoader)
Create a PropertySource based on Properties loaded from the given resource location and use the given class loader to load the resource, assuming it is prefixed withclasspath:
.ResourcePropertySource(String name, String location)
Create a PropertySource having the given name based on Properties loaded from the given resource location.ResourcePropertySource(String name, String location, ClassLoader classLoader)
Create a PropertySource having the given name based on Properties loaded from the given resource location and using the given class loader to load the resource (assuming it is prefixed withclasspath:
).ResourcePropertySource(String name, Resource resource)
Create a PropertySource having the given name based on Properties loaded from the given encoded resource.ResourcePropertySource(String name, EncodedResource resource)
Create a PropertySource having the given name based on Properties loaded from the given encoded resource.ResourcePropertySource(Resource resource)
Create a PropertySource based on Properties loaded from the given resource.ResourcePropertySource(EncodedResource resource)
Create a PropertySource based on Properties loaded from the given resource.
方法概要
所有方法 实例方法 具体方法 修饰符和类型 方法 说明 ResourcePropertySource
withName(String name)
Return a potentially adapted variant of thisResourcePropertySource
, overriding the previously given (or derived) name with the specified name.ResourcePropertySource
withResourceName()
Return a potentially adapted variant of thisResourcePropertySource
, overriding the previously given name (if any) with the original resource name (equivalent to the name generated by the name-less constructor variants).从类继承的方法 org.springframework.core.env.MapPropertySource
containsProperty, getProperty, getPropertyNames
构造器详细资料
ResourcePropertySource
public ResourcePropertySource(String name, EncodedResource resource) throws IOException
Create a PropertySource having the given name based on Properties loaded from the given encoded resource.- 抛出:
IOException
ResourcePropertySource
public ResourcePropertySource(EncodedResource resource) throws IOException
Create a PropertySource based on Properties loaded from the given resource. The name of the PropertySource will be generated based on thedescription
of the given resource.- 抛出:
IOException
ResourcePropertySource
public ResourcePropertySource(String name, Resource resource) throws IOException
Create a PropertySource having the given name based on Properties loaded from the given encoded resource.- 抛出:
IOException
ResourcePropertySource
public ResourcePropertySource(Resource resource) throws IOException
Create a PropertySource based on Properties loaded from the given resource. The name of the PropertySource will be generated based on thedescription
of the given resource.- 抛出:
IOException
ResourcePropertySource
public ResourcePropertySource(String name, String location, ClassLoader classLoader) throws IOException
Create a PropertySource having the given name based on Properties loaded from the given resource location and using the given class loader to load the resource (assuming it is prefixed withclasspath:
).- 抛出:
IOException
ResourcePropertySource
public ResourcePropertySource(String location, ClassLoader classLoader) throws IOException
Create a PropertySource based on Properties loaded from the given resource location and use the given class loader to load the resource, assuming it is prefixed withclasspath:
. The name of the PropertySource will be generated based on thedescription
of the resource.- 抛出:
IOException
ResourcePropertySource
public ResourcePropertySource(String name, String location) throws IOException
Create a PropertySource having the given name based on Properties loaded from the given resource location. The default thread context class loader will be used to load the resource (assuming the location string is prefixed withclasspath:
.- 抛出:
IOException
ResourcePropertySource
public ResourcePropertySource(String location) throws IOException
Create a PropertySource based on Properties loaded from the given resource location. The name of the PropertySource will be generated based on thedescription
of the resource.- 抛出:
IOException
方法详细资料
withName
public ResourcePropertySource withName(String name)
Return a potentially adapted variant of thisResourcePropertySource
, overriding the previously given (or derived) name with the specified name.- 从以下版本开始:
- 4.0.4
withResourceName
public ResourcePropertySource withResourceName()
Return a potentially adapted variant of thisResourcePropertySource
, overriding the previously given name (if any) with the original resource name (equivalent to the name generated by the name-less constructor variants).- 从以下版本开始:
- 4.1